55z^2+735z=0

Solution for 55z^2+735z=0 equation:

55z^2+735z=0

a = 55; b = 735; c = 0;
Δ = b2-4ac
Δ = 7352-4·55·0
Δ = 540225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{540225}=735$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(735)-735}{2*55}=\frac{-1470}{110}
=-13+4/11
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(735)+735}{2*55}=\frac{0}{110}
=0
$